编码练习4

练习1：
写一个函数，实现遍历一个数字和字母掺杂的字符串，如果碰到字母则替换成*，最后隔开的数字作为整体计算求和。如"ab34aa243dd78eww89"，则替换成的结果为：“342437889"，求和结果为："7915**17”

s = "ab34aa243dd78eww89"
result = ""
count = 0
for i in s:
    if i>='a' and i<='z':
        result+="*"
    else:
        result+=i

print(result)
result = result.replace("*"," ")
for i in result.split():
    count+=int(i)

print(count)

import re
s = "ab34aa243dd78eww89"
result = ""
s=re.sub(r"[a-z]","*",s)
arr1=re.split("\\*+",s)  #['', '34', '243', '78', '89']
for i in range(len(arr1)):
    count=0
    if arr1[i].isdigit():
        for j in arr1[i]:
            count+=int(j)
    if count!=0:
        arr1[i]=str(count)

arr2=re.split("\\d+",s)  #['**', '**', '**', '***', '']
for i in range(len(arr1)):
    result+=arr1[i]+arr2[i]

print(result)

练习2：
一个字符串 i am learning，请按照如下规则转换为数字
abcd-5,efgh-10,ijkl-15,mnop-20,qrst-25,uvwx-30,yz-35
转换正确结果为：15 520 1510 52520152010

rule="abcd-5,efgh-10,ijkl-15,mnop-20,qrst-25,uvwx-30,yz-35"
rule=rule.split(",")
s="i am learning"
result=""
for i in s:
    for r in rule:
        if i in r:
            result+=r.split("-")[1]
            break
    else:
        result+=i

print(result)

练习3：
从控制台输入一串字母，判断是否是连续相同字母，是则输出True，否则输出Flase。

def judge_str():
    s=input("请输入一串字符串：")
    if s[0]*len(s)==s and ((s[0]>='a' and s[0]<='z') or (s[0]>='A' and s[0]<='Z')):
        return True
    else:
        return False

judge_str()