Leetcode House Robber

最新推荐文章于 2021-08-05 11:16:28 发布

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最新推荐文章于 2021-08-05 11:16:28 发布

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分类专栏： leetcode dynamic programming leetcode

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本文探讨了作为专业抢劫者如何在一条街道上抢劫房屋而不触发警报的最大收益策略。通过动态规划方法，文章详细解释了如何在不抢劫相邻房屋的情况下，最大化抢劫总金额。

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You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected and it will automatically contact the police if two adjacent houses were broken into on the same night.

Given a list of non-negative integers representing the amount of money of each house, determine the maximum amount of money you can rob tonight without alerting the police.

比较显然的dp。。。
[code]

public class Solution {
    public int rob(int[] nums) {
        if(nums.length==0)return 0;
        int dp[][]=new int[nums.length][2];
        dp[0][0]=nums[0];
        dp[0][1]=0;
        for(int i=1;i<nums.length;i++)
        {
            dp[i][0]=dp[i-1][1]+nums[i];
            dp[i][1]=Math.max(dp[i-1][0], dp[i-1][1]);
        }
        return Math.max(dp[nums.length-1][0], dp[nums.length-1][1]);
    }
}