c 查询整型中1 的个数

#include "stdafx.h"
#include <stdlib.h>
#include <stdio.h>

unsigned int cal(unsigned n)
{
	unsigned c = 0;
	printf("%x\n",n);
	while (n>0)
	{
		c += n&1;
		n=n>>1;
		
	}
	return c;
}