C语言实现简单万年历

最新推荐文章于 2021-05-18 10:33:21 发布

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最新推荐文章于 2021-05-18 10:33:21 发布 · 1.3w 阅读

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CC 4.0 BY-SA版权

#include <stdio.h>
#include<stdlib.h>
int year, month;
int run[12] = { 31,29,31,30,31,30,31,31,30,31,30,31 };
int ping[12] = { 31,28,31,30,31,30,31,31,30,31,30,31 };
char week[7][10] = { "SUN","MON","TUE","WED","THU","FRI","SAT" };

bool IsLeap(int year)
{
	if (year % 400 == 0 || (year % 4 == 0 && year % 100 != 0))	//判断闰年
	{
		return true;
	}
	else
	{
		return false;
	}
}
void PrintStar()
{
	printf("\t\t\t万年历\t\t\t\n");
	printf("****************************************************\n");
	for (int i = 0; i < 7; i++)
	{
		printf("%s\t", week[i]);
	}
	printf("\n");
}
int DaySum(int year, int month)
{
	int sum = 0;
	for (int i = 1990; i < year; i++)
	{
		if (IsLeap(i))
		{
			sum += 366;
		}
		else
		{
			sum += 365;
		}
	}
	for (int i = 0; i < month - 1; i++)
	{
		if (IsLeap(year))
		{
			sum += run[i];
		}
		else
		{
			sum += ping[i];
		}
	}
	return sum;
}

void PrintCal(int sum, int year, int month)
{
	int nRes, nT