Given an integer n, generate a square matrix filled with elements from 1 to n2 in spiral order.
For example,
Given n = 3,
[ [ 1, 2, 3 ], [ 8, 9, 4 ], [ 7, 6, 5 ] ]» Solve this problem
修改了Spiral Matrix的代码。
class Solution {
public:
vector<vector<int> > generateMatrix(int n) {
// Start typing your C/C++ solution below
// DO NOT write int main() function
vector<vector<int> > ans;
for (int i = 0; i < n; i++) {
vector<int> t = vector<int>(n, -1);
ans.push_back(t);
}
int step[][2] = {{0, 1}, {1, 0}, {0, -1}, {-1, 0}};
int dir = 0, x = 0, y = 0;
for (int i = 1; i <= n * n; i++) {
ans[x][y]= i;
if (x + step[dir][0] == n || x + step[dir][0] < 0 ||
y + step[dir][1] == n || y + step[dir][1] < 0 ||
ans[x + step[dir][0]][y + step[dir][1]] != -1) {
dir = dir == 3 ? 0 : dir + 1;
}
x += step[dir][0];
y += step[dir][1];
}
return ans;
}
};
本文介绍了一个C++实现的螺旋矩阵生成算法,该算法能够根据给定的整数n生成一个n×n的矩阵,矩阵元素从1到n²按螺旋顺序填充。通过巧妙地使用方向数组和边界检查实现了螺旋式的填充过程。
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