hihoCoder 1122 二分图二•二分图最大匹配之匈牙利算法

#include <iostream>
#include <cstdio>
#include <cstring>
using namespace std;

int n,m;
int edge[1005][1005];
int vis1[1005];
int vis2[10005];


bool search_path(int u){
    for(int v = 1; v <= n; v++){
        if(edge[u][v] && !vis2[v]){
            vis2[v] = true;
            if(vis1[v] == -1 || search_path(vis1[v])){
                vis1[v] = u;
                vis1[u] = v;
                return true;
            }
        }
    }
    return false;
}

int MaxMatch(){
    int u,ans = 0;
    memset(vis1,-1,sizeof(vis1));
    for(int i = 1; i <= n; i++){
        if(vis1[i] == -1){
            memset(vis2,0,sizeof(vis2));
            if(search_path(i))
                ans++;
        }
    }
    return ans;
}

int main(){
    while(~scanf("%d%d",&n,&m)){
        int x,y;
        memset(edge,0,sizeof(edge));
        for(int i = 0; i < m; i++){
            scanf("%d%d",&x,&y);
            edge[x][y] = edge[y][x] = 1;
        }
        printf("%d\n",MaxMatch());
    }
    return 0;
}