Apache CXF requires java version 1.5 or higher. You are currently usin g java version 1.7.

作者在使用Apache CXF2.4.2版本在Windows7系统下编译样例项目时遇到错误,通过修改配置解决了Java版本不匹配的问题,并进一步排查了编译文件结构,最终解决了目标不存在的问题。
gentlemen:

It would seem to be impossible to follow the readme.txt directions provided
with Apache CXF 2.4.2 in the samples directory on Windows 7 Ultimate edition.
These instructions are intended to compile all of the sample projects using Ant.

I set up the environment as required. The environment seemed to check out using
a command shell window.
I set the working directory to: "C:\Program Files\Apache Software
Foundation\apache-cxf-2.4.2\samples"

I tried the command: "ant -buildfile .\common_build.xml war"

I failed with this message:

BUILD FAILED
C:\Program Files\Apache Software Foundation\apache-cxf-2.4.2\samples\common_buil
d.xml:75: Apache CXF requires java version 1.5 or higher. You are currently usin
g java version 1.7.

I managed to work around that error by changing "common_build.xml"

I changed this:

    <condition property="is. java .version.15">
        <or>
            <equals arg1="${ant. java .version}" arg2="1.5"/>
            <equals arg1="${ant. java .version}" arg2="1.6"/>
        </or>
    </condition>

    <fail message="Apache CXF requires java version 1.5 or higher. You are
currently using java version ${ant. java .version}."
        unless="is. java .version.15"/>

to this:

    <condition property="is. java .version.15">
        <or>
            <equals arg1="${ant. java .version}" arg2="1.5"/>
            <equals arg1="${ant. java .version}" arg2="1.6"/>
            <equals arg1="${ant. java .version}" arg2="1.7"/>
     </or>
    </condition>

    <fail message="Apache CXF requires java version 1.5 or higher. You are
currently using java version ${ant. java .version}."
        unless="is. java .version.15"/>

I then got past the java Version error message.

I next tried "ant -buildfile .\common_build_PS.xml war"

I failed with this message:

C:\Program Files\Apache Software Foundation\apache-cxf-2.4.2\samples>ant -buildf
ile .\common_build_PS.xml war
Buildfile: C:\Program Files\Apache Software Foundation\apache-cxf-2.4.2\samples\
common_build_PS.xml
 [loadfile] Do not set property srcbuild.classpath as its length is 0.

BUILD FAILED
Target "war" does not exist in the project "cxf  build file".

Total time: 1 second

I examined the buildfile, and verified that indeed there is no "target name"
war in this file.

I did some more digging and discovered that the "FULL WAR" build should happen
by default since about CXF 2.0.2.

So I tried this command:
"ant -buildfile .\common_build_PS.xml"


I failed with this message:
C:\Program Files\Apache Software Foundation\apache-cxf-2.4.2\samples>ant -buildf
ile .\common_build_PS.xml
Buildfile: C:\Program Files\Apache Software Foundation\apache-cxf-2.4.2\samples\
common_build_PS.xml
 [loadfile] Do not set property srcbuild.classpath as its length is 0.

maybe.generate.code:
 [loadfile] Do not set property srcbuild.classpath as its length is 0.

BUILD FAILED
C:\Program Files\Apache Software Foundation\apache-cxf-2.4.2\samples\common_buil
d_PS.xml:120: The following error occurred while executing this line:
Target "generate.code" does not exist in the project "cxf  build file".

Total time: 1 second

I am running out of ideas here. The buildfiles were almost exactly the same for
versions 2.3.6, 2.2.12, and 2.0.10

Also, I cannot find any installation instructions per se.

The

CXF 2.4.2 Release Notes talk about

Installation Prerequisites ( which I completed)
and


Building the Samples ( which I cannot do, as seen above)
but do not say anything about performing the actual installation.

Can you help me please?

Thank you,
Patrick Sofin
719-963-4037
pasofin@xxxxxxxxx
### Java中 `org.apache.cxf.interceptor.Fault` 错误分析 当遇到 `org.apache.cxf.interceptor.Fault` 错误并伴随 `java.lang.String cannot be cast to` 的提示时,通常表明在 CXF WebService 中存在数据类型的不匹配问题。以下是可能的原因及其解决方案: #### 1. 数据类型不一致 如果客户端传递的数据类型与服务端期望的类型不符,则可能导致此类错误。例如,在引用[2]中提到的情况[^2],字符串被错误地解析为 JSON 对象。 - **原因**: 客户端发送的是原始字符串而非实际的对象实例。 - **解决方法**: - 确保客户端和服务端定义的 DTO 类型完全一致。 - 如果使用了自动生成的 WSDL 文件,请重新生成客户端代码以同步最新的服务端结构。 ```java // 示例:确保对象正确序列化和反序列化 JSONObject jsonObject = new JSONObject(); jsonObject.put("key", "value"); String jsonString = jsonObject.toJSONString(); // 反序列化回对象 JSONObject parsedObject = JSON.parseObject(jsonString); System.out.println(parsedObject.getString("key")); ``` --- #### 2. XML Wrapper 元素不匹配 CXF 使用 SOAP 协议传输数据时,可能会因为 XML Wrapper 元素名称不同而导致异常。例如,引用[3]中的情况[^3]描述了一个类似的场景。 - **原因**: 方法签名或参数封装方式不符合预期。 - **解决方法**: - 检查服务端接口是否正确标注了 `@WebParam` 和 `@XmlElementWrapper` 注解。 - 验证 WSDL 文件中定义的服务契约是否与实现保持一致。 ```java @WebService(targetNamespace = "http://webservice/") public interface HelloService { @WebMethod public String sayHello(@WebParam(name = "name") String name); } ``` --- #### 3. 序列化/反序列化机制冲突 某些情况下,即使数据类型看似匹配,但由于不同的库处理逻辑差异(如 FastJSON、Jackson 或 JAXB),仍可能出现无法转换的问题。 - **原因**: 不同框架对同一数据格式的理解可能存在偏差。 - **解决方法**: - 统一项目中使用的序列化工具版本。 - 明确指定输入输出的内容类型(Content-Type)。例如,设置 HTTP 请求头为 `application/json` 或 `text/xml`。 ```xml <jaxb:globalBindings generateElementProperty="false"/> <!-- 上述配置可以避免不必要的 JAXBElement 封装 --> ``` --- #### 4. 自定义异常处理器 为了更好地捕获和调试这类问题,可以在 CXF 中引入自定义拦截器来记录详细的上下文信息。 - **实现步骤**: - 创建一个继承自 `AbstractPhaseInterceptor<Message>` 的类。 - 在其中重写 `handleMessage` 方法,用于捕获潜在的类型转换错误。 ```java import org.apache.cxf.interceptor.AbstractPhaseInterceptor; import org.apache.cxf.message.Message; public class CustomFaultInterceptor extends AbstractPhaseInterceptor<Message> { public CustomFaultInterceptor() { super(Phase.RECEIVE); } @Override public void handleMessage(Message message) throws Fault { try { Object body = message.getContent(List.class).get(0); if (body instanceof String && !((String) body).startsWith("{")) { throw new RuntimeException("Invalid payload format!"); } } catch (Exception e) { throw new Fault(e); } } } ``` --- ### 总结 针对 `org.apache.cxf.interceptor.Fault` 错误以及 `java.lang.String cannot be cast to` 提示,应重点排查以下几个方面: - 数据类型一致性; - XML Wrapper 元素命名规则; - 序列化/反序列化的兼容性; - 引入定制化日志或拦截器辅助诊断。 ---
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