一个数的n进制

#include <iostream>
#include <cstring>
  
using namespace std;  
  
int main()  
{
	int n,m;
	cin>>n>>m;
	char a[1001];
	int i=0;
	while(n!=0){
		a[i++] = n%m + '0';
		n = n/m;
	}
	strrev(a);
	cout<<a;
    return 0;  
}