百炼2965 玛雅历

对于某一个特定的输入形式，比如这道题中的“10. zac 0”的10.

这个点可以采用scanf(“%d. %s %d”,&d,m,&y);

不用将d.用字符串的方式存储，直接在输入的格式里进行设置就ok了

通过实践总结出来的。

这章的关于时间操作的题目的思路都挺正确的。

 

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

//先将Haab历转换为度过了多少days函数


int main()
{
    //先将Haab历转换为度过了多少days，再将days转换为Tzolkin历
    int n;
    scanf("%d",&n);
    printf("%d\n",n);
    int i,y;
   int j;
    //表示日历方式 初始化，充分利用字符串及其下标的对应关系
    char Hm[20][10]={"pop","no","zip","zotz","tzec","xul","yoxkin","mol","chen"
                    ,"yax","zac","ceh","mac","kankin","muan","pax","koyab","cumhu","uayet"};

    char Tname[20][10]={"imix","ik","akbal","kan","chicchan","cimi","manik","lamat"
                ,"muluk","ok","chuen","eb","ben","ix","mem","cib","caban","eznab","canac","ahau"};

    int d;
    char m[10];
    //转换days
    //对于多输入多输出，可将中间结果作为数组的形式存放，节省内存空间，简化代码
    //事实证明我想多了。。。根本不用，一行输入对应一行输出


while(n--)
{
    scanf("%d. %s %d",&d,m,&y);
    int days=0;
    for(i=0;i<20;i++)
    {
        if(strcmp(m,Hm[i])==0)
            break;
    }
     days=y*365+i*20+d;//总共的天数，从0开始算起
   printf("%d %s %d\n",1+days%13,Tname[days%20],days/260);

}

return 0;
}