有关数组指针和指针数组容易混淆,本文举例说明两者的区别,并加以分析。
基本概念:
-------------------指针---------------------
int a=1;
int *p=&a;
----------------指针的指针------------------
int **p2p=&p;
-----------------简单数组--------------------
int b[20];
-----------------指针数组--------------------
int *p[10]; //指针数组,含有10个指针元素,
//即每一个元素都是一个指针
-----------------数组指针---------------------
int (*p)[10]; //这个指针用来指向含有10个整数
//元素的数组分析如下代码:
#include<iostream>
#include<typeinfo>
using namespace std;
int main()
{
int a=10;
int b[2]={6,8};
int *p=&a;
int **p2p=&p;
int *pb[2]={&a,&a};
int (*p2b)[2]=&b;
cout<<"declaration [int a=10] type=="<<typeid(a).name()<<endl;
cout<<"declaration [int b[2]={6,8}] type=="<<typeid(b).name()<<endl;
cout<<"declaration [int *p=&a] type=="<<typeid(p).name()<<endl;
cout<<"declaration [int **p2p=&p] type=="<<typeid(p2p).name()<<endl;
cout<<"declaration [int *pb[2]={&a,&a}] type=="<<typeid(pb).name()<<endl;
cout<<"declaration [int (*p2b)[2]=&b] type=="<<typeid(p2b).name()<<endl;
return 0;
}
#include<typeinfo>
using namespace std;
int main()
{
int a=10;
int b[2]={6,8};
int *p=&a;
int **p2p=&p;
int *pb[2]={&a,&a};
int (*p2b)[2]=&b;
cout<<"declaration [int a=10] type=="<<typeid(a).name()<<endl;
cout<<"declaration [int b[2]={6,8}] type=="<<typeid(b).name()<<endl;
cout<<"declaration [int *p=&a] type=="<<typeid(p).name()<<endl;
cout<<"declaration [int **p2p=&p] type=="<<typeid(p2p).name()<<endl;
cout<<"declaration [int *pb[2]={&a,&a}] type=="<<typeid(pb).name()<<endl;
cout<<"declaration [int (*p2b)[2]=&b] type=="<<typeid(p2b).name()<<endl;
return 0;
}
输出结果:
declaration [int a=10] type==int
declaration [int b[2]={6,8}] type==int [2]
declaration [int *p=&a] type==int *
declaration [int **p2p=&p] type==int * *
declaration [int *pb[2]={&a,&a}] type==int * [2]
declaration [int (*p2b)[2]=&b] type==int (*)[2]
declaration [int b[2]={6,8}] type==int [2]
declaration [int *p=&a] type==int *
declaration [int **p2p=&p] type==int * *
declaration [int *pb[2]={&a,&a}] type==int * [2]
declaration [int (*p2b)[2]=&b] type==int (*)[2]
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