1043 输出PATest(基于Python3)
`a=input()
x=‘PATest’
c={}
for i in x:
if i in a:
c[i]=a.count(i)
m=1
n=’’
while m<= max(c[i] for i in c):
for i in c:
if m<=c[i]:
n+=i
m+=1
print(n)
这段代码展示了如何使用Python3处理输入字符串,统计字符出现次数,并构建新的字符串。程序通过遍历输入字符串,计算每个字符的出现频率,并按照频率构建新字符串。
1043 输出PATest(基于Python3)
`a=input()
x=‘PATest’
c={}
for i in x:
if i in a:
c[i]=a.count(i)
m=1
n=’’
while m<= max(c[i] for i in c):
for i in c:
if m<=c[i]:
n+=i
m+=1
print(n)
465
261

被折叠的 条评论
为什么被折叠?