What day is it

BeToBe_

于 2018-05-15 17:34:00 发布

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分类专栏： C 数据结构

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本文介绍了一种将特定日期转换为对应星期几的算法实现。通过分析不同月份天数及闰年规则，确保了日期的有效性，并利用公式计算出输入日期对应的星期。此算法适用于多种编程竞赛场景。

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Description

Today is Saturday, 17th Nov,2007. Now, if i tell you a date, can you tell me what day it is ?

Input

There are multiply cases.
One line is one case.
There are three integers, year(0<year<10000), month(0<=month<13), day(0<=day<32).

Output

Output one line.
if the date is illegal, you should output "illegal". Or, you should output what day it is.

Sample Input

2007 11 17

Sample Output

Saturday

Source

HDU 2007-11  Programming Contest_WarmUp

Submit

#include<stdio.h>
#include<string.h>
#include<stdlib.h>

int check_ord_day(int year, int month)
{
	int num;
	switch (month)
	{
	case 1:
	case 3:
	case 5:
	case 7:
	case 8:
	case 10:
	case 12:
		num = 31;
		break;
	case 2:
		if (((year % 4 == 0) && (year % 100 != 0)) || (year % 400 == 0))
			return num = 29;
		else
			return num = 28;
		break;
	case 4:
	case 6:
	case 9:
	case 11:
		num = 30;
		break;
	}
	return num;
}

int check(int year, int month, int day)
{
	if (year <= 0 || month <= 0 || month > 12 || day <= 0 || day > check_ord_day(year, month))
		return 1;
}
int week_change(int year, int month, int day)
{
	int s = 0;
	if (month == 1) { month = 13; year--; }
	if (month == 2) { month = 14; year--; }
	s = (day + 2 * month + 3 * (month + 1) / 5 + year + year / 4 - year / 100 + year / 400) % 7;
	return s;

}
char* s_change(int s)
{
	char *str;
	switch (s)
	{
	case 0:
		str = "Monday";
		break;
	case 1:
		str = "Tuesday";
		break;
	case 2:
		str = "Wednesday";
		break;
	case 3:
		str = "Thursday";
		break;
	case 4:
		str = "Friday";
		break;
	case 5:
		str = "Saturday";
		break;
	case 6:
		str = "Sunday";
		break;
	}
	return str;
}
int main()
{
	int year, month, day;
	while (scanf("%d%d%d", &year, &month, &day) != EOF)
	{
		if (check(year, month, day)==1)
		{
		    printf("illegal\n");

		}
		else
        {

            int s;
			s = week_change(year, month, day);

			char *ss;
			ss = s_change(s);
			printf("%s\n",ss);

        }
	}
	return 0;
}

Wrong Answer

#include<iostream>
#include<cstdio>
#include<cstring>

using namespace std;

int d[2][13]={{0,31,28,31,30,31,30,31,31,30,31,30,31},
    {0,31,29,31,30,31,30,31,31,30,31,30,31}};
char c[7][10]={"Monday","Tuesday","Wednesday","Thursday","Friday","Saturday","Sunday"};


int check(int year,int month,int day)
{
    int i;
    if (((year % 4 == 0) && (year % 100 != 0)) || (year % 400 == 0))
        i=1;
    else i=0;
    if(year<=0||month<=0||month>12||day<=0||day > d[i][month])
        return 1;
}

int week_change(int year,int month,int day)
{
    int s = 0;
    if (month == 1) { month = 13; year--; }
    if (month == 2) { month = 14; year--; }
    s = (day + 2 * month + 3 * (month + 1) / 5 + year + year / 4 - year / 100 + year / 400) % 7;
    return s;
}
int main()
{
    int year,month,day;
    while(scanf("%d%d%d", &year, &month, &day) != EOF)
    {
        if(check(year,month,day)==1)
            puts("illegal");
        else
        {
            int s;
            s=week_change(year,month,day);
            puts(c[s]);
        }
    }
    return 0;
}