package com.tongbanjie.trade.test.base;
import java.util.concurrent.TimeUnit;
import java.util.concurrent.atomic.AtomicInteger;
/**
* 测试并发累加
* @author huangqun
*
*/
public class TestConcurrentPlusPlus {
public static int count = 0;
public volatile static int volatileCount = 0;
public static int synchronizedCount = 0;
public static AtomicInteger atomicCount = new AtomicInteger(0);
public volatile static AtomicInteger volatileAtomicCount = new AtomicInteger(0);
public static void main(String[] args) {
final Object lock = new Object();
for (int i = 0; i < 50000; i++) {
new Thread(new Runnable() {
@Override
public void run() {
count++;
volatileCount++;
synchronized (lock) {
synchronizedCount++;
}
atomicCount.incrementAndGet();
volatileAtomicCount.incrementAndGet();
}
}).start();
}
// 休息5秒, 保证线程中的计算完成
try {
TimeUnit.SECONDS.sleep(5);
} catch (InterruptedException e) {
e.printStackTrace();
}
System.out.println("线程并发执行对计数器累计5000次,看并发结果!");
System.out.println("count=" + count);
System.out.println("volatileCount=" + volatileCount);
System.out.println("synchronizedCount=" + synchronizedCount);
System.out.println("atomicCount=" + atomicCount.get());
System.out.println("volatileAtomicCount=" + volatileAtomicCount.get());
}
}
解决并发下累计的问题
最新推荐文章于 2025-07-11 12:11:26 发布
本文通过创建多线程并发累加计数器的方式,演示了不同同步机制下的计数结果。测试包括普通变量、volatile变量、synchronized块及AtomicInteger的表现。

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