A strange lift hdu1548 Dijkstra算法

MPLAB修改工程名称方法 修改工程名称方法 如下图所示,工程名称为:Loar_V1.0_20210205 现将该工程名称修改为:Loar_V1.1_20210205 修改方法: ①找到工程文件路径,将工程名称修改为Loar_V1.1_20210205 注意:此时打开变成进行编译,会报错:Loar_V1.1_20210205.production.hex does not exist or is not an executable, ②找到工程下的 nbproject 文件夹 ③将nbproject文件夹下的文件全部打开,并且将 阅读详情

http://acm.hdu.edu.cn/showproblem.php?pid=1548

Dijkstra算法:单源最短路径问题

——包括确定起点的最短路径问题,确定终点的最短路径问题(与确定起点的问题相反,该问题是已知终结结点,求最短路径的问题。在无向图中该问题与确定起点的问题完全等同,在有向图中该问题等同于把所有路径方向反转的确定起点的问题。)

确定起点终点的最短路径问题
——即已知起点和终点,求两结点之间的最短路径。

Floyd算法:全局最短路径问题

——求图中所有的最短路径。

#include <iostream>
using namespace std;
#define N 205
#define INF 0x7ffffff
int lift[N][N],dir[N];
bool visited[N];

int main(){
#ifndef ONLINE_JUDGE
	freopen("1548in.txt","r",stdin);
#endif
	int n,a,b,i,j,ki,low,t;
	while (scanf("%d",&n)!=EOF&&n){
		scanf("%d%d",&a,&b);
		for (i=1;i<=n;i++)
			for (j=1;j<=i;j++)
				lift[i][j]=lift[j][i]=INF;
		for (i=1;i<=n;i++){
			scanf("%d",&ki);
			if (i-ki>=1)
				lift[i][i-ki]=1;
			if (i+ki<=n)
				lift[i][i+ki]=1;
		}
		for (i=1;i<=n;i++){
			lift[i][i]=0;
			dir[i]=lift[a][i];
		}
		memset(visited,false,sizeof(visited));
		dir[a]=0;
		visited[a]=true;
		for (ki=1;ki<n;ki++){
			low=INF+1;
			for (i=1;i<=n;i++)
				if (!visited[i]&&dir[i]<low){
					low=dir[i];
					t=i;
				}
			visited[t]=true;
			for (i=1;i<=n;i++)
				if (!visited[i]&&dir[t]+lift[t][i]<dir[i])
					dir[i]=dir[t]+lift[t][i];
		}
		if (dir[b]<INF)
			printf("%d\n",dir[b]);
		else printf("-1\n");
	}
	return 0;
}


Qt6安装保姆级教程:从国内镜像下载到配置避坑指南(附清华/中科大源) 本文提供详细的Qt6安装与配置指南,重点介绍如何利用清华大学、中国科学技术大学等国内镜像源解决下载速度慢的问题。内容涵盖在线安装器获取、组件选择策略、环境变量配置以及常见编译与部署问题的排查方法,旨在帮助国内开发者高效、顺畅地完成Qt6开发环境搭建。 阅读详情

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HDU1548——A strange lift(最短路径:dijkstra算法)

A strange lift DescriptionThere is a strange lift.The lift can stop can at every floor as you want, and there is a number Ki(0 <= Ki <= N) on every floor.The lift have just two buttons: up and ...

weixin_30901729的博客 137

【HDU 1548 --- A strange lift】BFS||最短路问题(floyd,dijkstra都可以)

【HDU 1548 --- A strange lift】BFS||最短路问题(floyd,dijkstra都可以) Description There is a strange lift.The lift can stop can at every floor as you want, and there is a number Ki(0 <= Ki <= N) on every f...

来日浅谈的博客 585

hdu 1548 A strange lift(bfs||dijkstra)

hdu 1548 A strange lift http://acm.hdu.edu.cn/showproblem.php?pid=1548 ProblemDescription Thereisastrangelift.Theliftcanstopcanateveryfloorasyouwant,andthereisanum...

diansitao5461的博客 164

【Dijkstra】-HDU-1548-A strange lift

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1548 题目描述: 有一个电梯,上面只有UP 和DOWN 两种按钮,每层楼梯有一个值,按下UP按钮就会上升这么多层,按下DOWN按钮就会下降这么多层。问对于给定的从A层到B层,至少需要按几次按钮? 解题思路: 还是基础的Dijkstra求最短路,注意判断边界条件,每条路径的花费都是1。 AC代

邂逅黛玛姑娘 957

hdu-1548 A strange lift

http://acm.hdu.edu.cn/showproblem.php?pid=1548

有一种力量叫乐观 685

HDU1548 A strange lift Dijkstra BFS

HDU1548 A strange lift Dijkstra BFS

htrdchh的博客 146

Hdu-1548 A strange lift

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1548 题目大意: 有一个建筑有N层,里面有一架电梯。给你一个起点层数和一个终点层数。there is a number Ki(0 ,在每一层都有一个按钮,按钮上面有一个数字,表示

飘过的小牛 1848
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