求一个数的N次方

最新推荐文章于 2023-11-22 18:17:02 发布

原创最新推荐文章于 2023-11-22 18:17:02 发布 · 918 阅读

0 ·

CC 4.0 BY-SA版权

文章标签：

#a的N次方

C++ 专栏收录该内容

51 篇文章

订阅专栏

本文介绍了一个使用C++实现的简单程序，该程序能够计算任意基数和指数的幂，并展示了如何处理整数和浮点数指数的情况。通过自定义幂运算函数与标准库pow函数的结合使用，实现了灵活的指数计算。

/*
 Enter 2 values for X and  Y separated by space, The press <enter>:  2.4 4.85
 2.4 to the power of 4.85 is = 69.8272
 Enter 2 values for X and  Y separated by space, The press <enter>:  3 4
 3 to the power of 4 is = 81
 */

#include <iostream>
#include <cmath>

double power(double x,  int count);


int main() {
    using std::cout;
    using std:: cin;

    double x , y;
    double p;
    cout << "Enter 2 values for X and  Y separated by space, The press <enter>:  ";
    cin >> x >> y;

    int tmp = y;
    if (y == tmp)
        p = power(x, tmp);
    else
        p = pow(x, y);

    cout << x << " to the power of " << y << " is = " << p << "\n";

    return 0;
}

double power(double x, int count) {
    double p = 1;

    while (count) {
        p *= x;
        count--;
    }

    return p;
}