J-find your present(2)

最新推荐文章于 2024-06-10 15:43:12 发布
原创 最新推荐文章于 2024-06-10 15:43:12 发布 · 258 阅读 · 0 ·
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本文介绍了一种使用位运算解决问题的方法，特别是通过异或运算找出数组中唯一出现奇数次的元素。文中详细解释了异或运算的基本法则及其应用场景。

运用位运算，真的强！！位运算法则，a^b=b^a   ,    (a^b)^c=a^(b^c)  ,   a^b^a=b   ,0^a=a,   a^a=0;

由于给的数组里都出现偶数次，只有一个出现奇数次，所以一直位运算，最后只剩下一个出现奇数次的

异或位运算：http://blog.youkuaiyun.com/tangyanzhi1111/article/details/21696943

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