OkHttp IllegalArgumentException

最新推荐文章于 2024-01-07 04:30:00 发布

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#HttpUrl #Okhttp #unexpected

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本文详细解析了使用Java构造HTTP URL时可能出现的IllegalArgumentException异常，并提供了正确的URL构造方式。通过实例展示了如何避免因URL格式不正确而引发的错误。

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java.lang.IllegalArgumentException: unexpected url

String url = /*错误写法*/"www.baidu.com";

String url = /*正确写法*/"http://www.baidu.com";

java.lang.IllegalArgumentException: unexpected scheme

HttpUrl build = new HttpUrl.Builder()/*错误写法*/.scheme("http://").build();

HttpUrl build = new HttpUrl.Builder()/*正确写法*/.scheme("http").build();

HttpUrl build = new HttpUrl.Builder()/*正确写法*/.scheme("https").build();

java.lang.IllegalArgumentException: unexpected host

HttpUrl build = new HttpUrl.Builder()/*错误写法*/.host("http://www.baidu.com").build();

HttpUrl build = new HttpUrl.Builder()/*正确写法*/.host("www.baidu.com").build();

java.lang.IllegalArgumentException: unexpected port

HttpUrl build = new HttpUrl.Builder()/*错误写法*/.port(-1).build();

HttpUrl build = new HttpUrl.Builder()/*正确写法port在(0 - 65535)*/.port(80).build();

测试案例

HttpUrl build = new HttpUrl.Builder()
            .scheme("http")
            .host("www.baidu.com")
            .port(80)
            .build();

更换URL案例

HttpUrl parse = HttpUrl.parse("http://www.baidu.com");

HttpUrl build = new HttpUrl.Builder().scheme(parse.scheme()).host(parse.host()).port(parse.port()).build();