买了10瓶酒，如果4个酒盖子或2个空酒瓶子可换1瓶酒，那么你最多可以喝几瓶酒？...

过年在家时，我弟给我出了个题，他说：“你买了10瓶酒，如果4个酒盖子或2个空酒瓶子可换1瓶酒，那么你最多可以喝几瓶酒？”于是我写了一下程序来计算。

// 4个盖子或两个瓶子可以换一瓶酒
        static void Main(string[] args)
        {
            // 一开始的酒数量
            int wineCount = 10;

            // 当前瓶子数量
            int bottleCount = wineCount;
            // 当前瓶盖数量
            int capCount = wineCount;
            // 得到的酒数量
            int getWine = wineCount;
            // 喝到的酒数量
            int getAllWine = wineCount;


            getAllWine = GetWineCount(bottleCount, capCount, getWine, getAllWine);

            Console.WriteLine($"喝到的酒数量：{getAllWine}");
            Console.ReadKey();
        }

        /// <summary>
        /// 
        /// </summary>
        /// <param name="bottleCount">瓶子数</param>
        /// <param name="capCount">瓶盖数</param>
        /// <param name="getWine">得到的酒数量</param>
        /// <returns></returns>
        static int GetWineCount(int bottleCount, int capCount, int getWine, int getAllWine)
        {
            if (bottleCount >= 2 || capCount >= 4)
            {
                getWine = bottleCount / 2 + capCount / 4;
                getAllWine += getWine;

                bottleCount = bottleCount % 2 + getWine;
                capCount = capCount % 4 + getWine;

                getAllWine = GetWineCount(bottleCount, capCount, getWine, getAllWine);
            }
            return getAllWine;
        }