Monica

DescriptionConsider two natural numbers A and B. Let S be the sum of all natural divisors of A^B. Determine S modulo 9901 (the rest of the division of S by 9901).InputThe only line contains the two nat

gg了gg了，感觉自己一直在刷水题，我noip2017要报零了预处理卡特兰数，预处理组合数，然后夹棍法放不走的状态，线性处理逆元#include <cstdio> #include <iostream> #include <cstring> using namespace std; const int MAXN = 2000000 + 10; const long long wys = 100000