178. Rank Scores

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本文介绍了一个SQL查询案例，用于对分数进行排名，并处理分数相同的情况，确保排名连续且没有空缺。

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https://leetcode.com/problems/rank-scores/description/

Write a SQL query to rank scores. If there is a tie between two scores, both should have the same ranking. Note that after a tie, the next ranking number should be the next consecutive integer value. In other words, there should be no "holes" between ranks.

+----+-------+
| Id | Score |
+----+-------+
| 1  | 3.50  |
| 2  | 3.65  |
| 3  | 4.00  |
| 4  | 3.85  |
| 5  | 4.00  |
| 6  | 3.65  |
+----+-------+

For example, given the above Scores table, your query should generate the following report (order by highest score):

+-------+------+
| Score | Rank |
+-------+------+
| 4.00  | 1    |
| 4.00  | 1    |
| 3.85  | 2    |
| 3.65  | 3    |
| 3.65  | 3    |
| 3.50  | 4    |
+-------+------+

select s.Score, CAST(temp.Rank as SIGNED) as Rank from Scores s left join 
(
	select t.Score, @rank := @rank + 1 as Rank from 
	(
		select Score
		from Scores
		group by Score 
		order by Score desc
	) t, (select @rank := 0) r
) temp on s.Score = temp.Score
order by s.Score desc