使用gson解析json,就得 json有一定的格式,要么是一个[],要么是一个{}
若是{},{},{} 外面又没有套[], 应该算格式不合理吧。
下面用个例子,简单的介绍gson如何解析json,仅使用~
先发两个json 内容
1、最外层是{}
{
"resp":"ok",
"result": {
"date": "2013-4-19 16:55:58",
"focus":
[
{
"title": "标题",
"summary": "简介",
"url": "http://www.ceshi.com"
},
{
"title": "标题22",
"summary": "简介22",
"url": "http://www.ceshi22.com"
}
],
"items": [
{
"name": "名称",
"id": "11",
"price": "88.88"
},
{
"name": "名称22",
"id": "22",
"price": "100"
}
]
}
}
2、外层是[]
[
{
"name": "zeng",
"age": "22",
"addr": "北京"
},
{
"name": "zhang",
"age": "20",
"addr": "上海"
},
{
"name": "wang",
"age": "25",
"addr": "深圳"
}
]
使用Gson,解析,关键的就是定义好类对象!
先{}的类
Bean.java
public class Bean {
// @SerializedName("resp")
// private String respone;//假如变量命名与解析数据不同,则加上@SerializedName("")
private String resp;
private Result result;
<pre name="code" class="java"> //....下面省略 set ,get
Result.java
public class Result {
private String date;
private List<FocusItem> focus;
private List<Item> items;
FocusItem.java
public class FocusItem {
private String title;
private String summary;
private String url;
Item.java
public class Item {
private String name;
private int id;
private float price;
下面的是[] 测试数组格式定义的一个的类
Info.java
public class Info {
private String name;
private int age;
private String addr;
解析代码,一个最外层是{} 一个是[]
private void parse() {
Gson gson = new Gson();
switch (type) {
case OBJ:
Bean fromJson = gson.fromJson(readContext, Bean.class);
System.out.println(fromJson.toString());
break;
case ARR:
Type type = new TypeToken<List<Info>>() {}.getType();
Object fromJson2 = gson.fromJson(readContext, type);
List<Info> list = (List<Info>) fromJson2;