LeetCode //C - 941. Valid Mountain Array

941. Valid Mountain Array

Given an array of integers arr, return true if and only if it is a valid mountain array.

Recall that arr is a mountain array if and only if:

  • arr.length >= 3
  • There exists some i with 0 < i < arr.length - 1 such that:
    • arr[0] < arr[1] < … < arr[i - 1] < arr[i]
    • arr[i] > arr[i + 1] > … > arr[arr.length - 1]
      在这里插入图片描述
       
Example 1:

Input: arr = [2,1]
Output: false

Example 2:

Input: arr = [3,5,5]
Output: false

Example 3:

Input: arr = [0,3,2,1]
Output: true

Constraints:
  • 1 < = a r r . l e n g t h < = 1 0 4 1 <= arr.length <= 10^4 1<=arr.length<=104
  • 0 < = a r r [ i ] < = 1 0 4 0 <= arr[i] <= 10^4 0<=arr[i]<=104

From: LeetCode
Link: 941. Valid Mountain Array


Solution:

Ideas:
  • Walk up while strictly increasing, stop at the peak.

  • Peak can’t be at ends.

  • Walk down while strictly decreasing.

  • If you end exactly at the last index, it’s a valid mountain.

Code:
bool validMountainArray(int* arr, int arrSize){
    if (arrSize < 3) return false;

    int i = 0;

    // climb up (strictly increasing)
    while (i + 1 < arrSize && arr[i] < arr[i + 1]) i++;

    // peak cannot be first or last
    if (i == 0 || i == arrSize - 1) return false;

    // go down (strictly decreasing)
    while (i + 1 < arrSize && arr[i] > arr[i + 1]) i++;

    // must finish exactly at the end
    return i == arrSize - 1;
}
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