LeetCode-------43. Multiply Strings(字符串的乘法运算)

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本文介绍了一种不使用BigInteger等内置库实现两个以字符串形式给出的大数相乘的方法。通过逐位相乘并进位的方式，实现了任意大小数字的乘法运算。

Given two numbers represented as strings, return multiplication of the numbers as a string.

Note:

The numbers can be arbitrarily large and are non-negative.
Converting the input string to integer is NOT allowed.
You should NOT use internal library such as BigInteger.

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public class Solution {
    public String multiply(String num1, String num2) {
        if (num1 == null || num2 == null) {
            return null;
        }
        
        int len1 = num1.length(), len2 = num2.length();
        int len3 = len1 + len2;
        int i, j, product, carry;

        int[] num3 = new int[len3];
        for (i = len1 - 1; i >= 0; i--) {
            carry = 0;
            for (j = len2 - 1; j >= 0; j--) {
                product = carry + num3[i + j + 1] +
                    Character.getNumericValue(num1.charAt(i)) *
                    Character.getNumericValue(num2.charAt(j));
                num3[i + j + 1] = product % 10;
                carry = product / 10;
            }
            num3[i + j + 1] = carry;
        }

        StringBuilder sb = new StringBuilder();
        i = 0;

        while (i < len3 - 1 && num3[i] == 0) {
            i++;
        }

        while (i < len3) {
            sb.append(num3[i++]);
        }

        return sb.toString();
    }
}