CreateMutex利用互斥对象实现线程同步示例01

最新推荐文章于 2024-03-25 13:54:28 发布

原创最新推荐文章于 2024-03-25 13:54:28 发布 · 798 阅读

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#include<windows.h>
#include<iostream.h>
DWORD WINAPI Fun1Proc(LPVOID lpParameter);
DWORD WINAPI Fun2Proc(LPVOID lpParameter);

int index =0 ;
int tickets = 100 ;
HANDLE hMutex;
void main()
{

HANDLE hThread1,hThread2;
hThread1 = CreateThread(NULL,0,Fun1Proc,NULL,0,NULL);
hThread2 = CreateThread(NULL,0,Fun2Proc,NULL,0,NULL);
CloseHandle(hThread1);
CloseHandle(hThread2);

hMutex = CreateMutex(NULL,FALSE,NULL);
Sleep(4000);

}

DWORD WINAPI Fun1Proc(LPVOID lpParameter)
{

while(true)
{

 WaitForSingleObject(hMutex,INFINITE);
 if(tickets>0)
 {
 cout<<"t1:"<<tickets--<<endl;
 }
 else
 {
 break;
 }
 ReleaseMutex(hMutex);
}
return 0;
}
DWORD WINAPI Fun2Proc(LPVOID lpParameter)
{
while(true)
{
 WaitForSingleObject(hMutex,INFINITE);
 if(tickets>0)
 {

 cout<<"t2:"<<tickets--<<endl;
 }
 else
 {
 break;
 }
 ReleaseMutex(hMutex);

}
 return 0;
}