HDU2051-2060题解

最新推荐文章于 2021-03-13 05:37:37 发布

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本文解析了两个算法题目，一是判断两数是否相等的简单算法，二是处理字符与数值运算的问题。通过代码示例，展示了如何在C++中使用条件运算符和字符数组进行操作。

文章目录

2051 Bitset

2054 A == B ?

Problem Description
Give you two numbers A and B, if A is equal to B, you should print “YES”, or print “NO”.
Input
each test case contains two numbers A and B.
Output
for each case, if A is equal to B, you should print “YES”, or print “NO”.
Sample Input
```
1 2
2 2
3 3
4 3
```
Sample Output
```
NO
YES
YES
NO
```

下面的两种写法都是错误的。

#include <cstdio>
int main() {
	int a, b;
	while (~scanf("%d%d", &a, &b)) {
		printf("%s\n", a == b ? "YES" : "NO");
	}
	return 0;
}

#include <string>
#include <cstdio>
#include <iostream>
using namespace std;
int main() {
	string s1, s2;
	while (cin >> s1 >> s2) {
		printf("%s\n", s1 == s2 ? "YES" : "NO");
	}
	return 0;
}

2055 An easy problem

#include <cstdio>
int main() {
	int n, p;
	scanf("%d\n", &n);
	char c;
	int letters[128] = {0};
	for (char i = 'A'; i <= 'Z'; i++) letters[i] = (i - 'A' + 1);
	for (char i = 'a'; i <= 'z'; i++) letters[i] = ('a' - i - 1); 
	while (n--) {
		scanf("%c %d\n", &c, &p);
		printf("%d\n", letters[c] + p);
	}
	return 0;
}