将十六进制字符串转为byte数组

最新推荐文章于 2024-06-12 08:52:55 发布

原创最新推荐文章于 2024-06-12 08:52:55 发布 · 9.6k 阅读

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文章标签：

#byte #bt #string #c #ui #.net

本文探讨了在.NET环境下将十六进制字符串高效转换为字节数组的不同方法，并通过实验证明了直接操作字节比使用标准库函数更高效。

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需求是这样有十六进制字符串要存为byte数组

如string st = "0A000000"，转为byte后为 byte[0]=10,byte[1]=0,byte[2]=0,byte[3]=0

因.net2.0可用Convert将十六进制字符串转为byte有现成的就用吧。代码如下:

public static byte[] writebytes1(string sBytes)

{

Stopwatch watch = new Stopwatch();

watch.Reset();

watch.Start();

Debug.Assert(sBytes.Length % 2 == 0, "数组长度错");

int pos = 0;

int len = (sBytes.Length / 2);

byte[] b = new byte[len];

int count = sBytes.Length;

for (int i = 0; i < count; i += 2)

{

b[pos] = Convert.ToByte(sBytes.Substring(i, 2), 16);

pos++;

}

watch.Stop();

Console.WriteLine("{0}:{1}", "writebytes1", watch.Elapsed);

return b;

}

但我觉得不够快，且发现我传的字符串长度都是8的整数倍，于是就用Convert.ToInt32以8位长度来转成uint32的数字再用BitConverter转为byte数组，但转换后数组内容与我的要求内容位置相返，所以再用Array.Reverse(Array)方法将数组返转，改了代码如下:

public static byte[] writebytes2(string sBytes)

{

Stopwatch watch = new Stopwatch();

watch.Reset();

watch.Start();

Debug.Assert(sBytes.Length % 2 == 0, "数组长度错");

Debug.Assert(sBytes.Length % 8 == 0, "数组长度不适合用于此方法");

int pos = 0;

int len = (sBytes.Length / 2);

byte[] b = new byte[len];

int count = sBytes.Length;

byte[] bt;

for (int i = 0; i < count; i += 8)

{

bt = BitConverter.GetBytes(Convert.ToInt32(sBytes.Substring(i, 8), 16));

Array.Reverse(bt);

bt.CopyTo(b, pos);

pos += 4;

}

watch.Stop();

Console.WriteLine("{0}:{1}", "writebytes2", watch.Elapsed);

return b;

}

测了一下没快多少，而且字符串加长后反而更慢，马上用Reflector看了一下发现是Array.Reverse的实现方法把速度拖下来了，没办法只能自已写整型转byte的方法不用BitConverter和Array.Reverse。代码如下:

public static byte[] writebytes3(string sBytes)

{

Stopwatch watch = new Stopwatch();

watch.Reset();

watch.Start();

Debug.Assert(sBytes.Length % 2 == 0, "数组长度错");

Debug.Assert(sBytes.Length % 8 == 0, "数组长度不适合用于此方法");

int pos = 0;

int len = (sBytes.Length / 2);

byte[] b = new byte[len];

int count = sBytes.Length;

for (int i = 0; i < count; i += 8)

{

ulong ui = Convert.ToUInt32(sBytes.Substring(i, 8), 16);

b[pos] = (byte)((ui & 0xFF000000) >> 24);

b[pos + 1] = (byte)((ui & 0x00FF0000) >> 16);

b[pos + 2] = (byte)((ui & 0x0000FF00) >> 8);

b[pos + 3] = (byte)((ui & 0x000000FF));

pos += 4;

}

watch.Stop();

Console.WriteLine("{0}:{1}", "writebytes3", watch.Elapsed);

return b;

}

测试了一下第三种方法只用了前两种大约1/3的时间。（奇怪的是后来我又用ToUInt64取64位来写同样的方法，却反而比用ToUInt32实现的方法慢，可惜无法了解底层API是如何实现Convert.ToUInt64,还请了解的能给我说说）

        static void Main(string[] args)
        {
            string st = "1E041800050013000022A322232C2323303B5C2D22A322232C232330"
              + "1E041D00060018000022A322232C2323303B5B5265645D5C2D22A322232C232330"
              + "1E041E00070019000022A322232C2323302E30303B5C2D22A322232C2323302E3030"
              + "1E04230008001E000022A322232C2323302E30303B5B5265645D5C2D22A322232C2323302E3030"
+ "1E0435002A003000005F2D22A3222A20232C2323305F2D3B5C2D22A3222A20232C2323305F2D3B5F2D22A3222A20222D225F2D3B5F2D405F2D"
+ "1E042C0029002700005F2D2A20232C2323305F2D3B5C2D2A20232C2323305F2D3B5F2D2A20222D225F2D3B5F2D405F2D" + "1E043D002C003800005F2D22A3222A20232C2323302E30305F2D3B5C2D22A3222A20232C2323302E30305F2D3B5F2D22A3222A20222D223F3F5F2D3B5F2D405F2D"
+ "1E0434002B002F00005F2D2A20232C2323302E30305F2D3B5C2D2A20232C2323302E30305F2D3B5F2D2A20222D223F3F5F2D3B5F2D405F2D";

            byte[] bt1 = writebytes1(st);
            byte[] bt2 = writebytes2(st);
            byte[] bt3 = writebytes3(st);

            for (int i = 0; i < bt1.Length; i++)
            {
                if (bt1[i] != bt2[i] || bt1[i] != bt3[i] )
                {
                    Console.WriteLine("err");
                    return;
                }
            }
            Console.WriteLine("ok");
        }