leetcode: Reverse Integer

同样比较简单和基础，练练手吧。  考虑有时间把之前刷过的几道也记录一下吧

public class Solution {
    public int reverse(int x) {
        boolean posi = true;
        if( x < 0 )
        {
            posi = false;
            x = 0-x;
        }
        int res = 0;
        while( x > 0)
        {
            res *= 10;
            int tmp = x % 10;
            res += tmp;
            x = x/10;
        }
        if( posi == false )
        {
            res = 0-res;
        }
        return res;
        
    }
}