等待分析

* 递归求n个数的积 */
/* 下面a[i]的取值是乱码 */
#include <stdio.h>
#include <stdlib.h>

double Ave(double *,int );

int main()
{

  int i=0,n=0;
  double aveval=0.0;
  double *a=NULL;

  printf("Please enter the count of numbers :\n");
  scanf("%d",&n);

  if(NULL==(a=(int *)malloc( sizeof(int)*n )))
  {

  printf(" Application space failure. ");
  exit(1);
  }

  printf("Please input %d numbers:\n",n);
  for(i=0;i<n;i++)
  {
  printf("It's the %dth number:",i+1);
  scanf("%f",&a[i]); /* 这儿有问题 */
  }
  for(i=0;i<n;i++)
  {
  printf("It's the %dth number:%f\n",i+1,a[i]);/* */
  }

  aveval=Ave(a,n-1);

  free(a);

  printf("avevalue=%f\n\n",aveval);

  printf("Please press any key to quit..\n");

  return 0;
}

double Ave(double *a,int n)
{
  if(n==0)
  return a[0];
  else
  {

  return (a[n]+Ave(a,n-1)*n)/(n+1); /* 个数必须加1，由于数组作用 */
  }