344.反转字符串
class Solution:
def reverseString(self, s: List[str]) -> None:
"""
Do not return anything, modify s in-place instead.
"""
left, right = 0, len(s) - 1
while(left < right):
s[left], s[right] = s[right], s[left]
left += 1
right -= 1
541. 反转字符串II
class Solution:
def reverseStr(self, s: str, k: int) -> str:
for i in range(0, len(s), 2*k):
s = s[:i] + s[i:i+k][::-1] + s[i+k:]
return s
卡码网:54.替换数字
s = str(input())
s2 = ''
digits = '0123456789'
for i in range(len(s)):
if s[i] in digits:
s2 += 'number'
else: s2 += s[i]
print(s2)
简单题秒了。

被折叠的 条评论
为什么被折叠?



