Given a non negative integer number num. For every numbers i in the range 0 ≤ i ≤ num calculate the number of 1’s in their binary representation and return them as an array.
Example:
For num = 5 you should return [0,1,1,2,1,2].
http://blog.youkuaiyun.com/martin_liang/article/details/50936387
class Solution {
public:
vector<int> countBits(int num) {
vector<int> dp(num+1);
dp[0] = 0;
for (int i=1; i<=num; i++)
{
if (i%2)
dp[i] = dp[i/2]+1;
else
dp[i] = dp[i/2];
}
return dp;
}
};