一个有关HTML的问题

最新推荐文章于 2025-07-03 10:20:33 发布

原创最新推荐文章于 2025-07-03 10:20:33 发布 · 270 阅读

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<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"
"http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=gb2312">
<title>无标题文档</title>
</head>

<body onLoad="add()">
<table BORDER id="table1"><tr id="row1"><td>中国移动</td><td id="ttd1"></td></tr></table>
<table BORDER id="table2"><tr id="row2"><td>中国联通</td><td id="ttd2"></td></tr></table>
<table BORDER id="table3"><tr id="row3"><td>中国电信</td><td id="ttd3"></td></tr></table>
<script>
  function add(){
   ttd1.innerHTML = "<input type='test' value=''>";
   ttd2.innerHTML = "<input type='test' value=''>";
   ttd3.innerHTML = "<input type='test' value=''>";
  }
</script>
<input type="text" name="pn" id="pn">
<input type="button" id="fz" value="分组" onClick="fenzu(pn.value，ttd1.firstChild.value,ttd2.firstChild.value,ttd3.firstChild.value)">
<script>
  function fenzu(str,ttd1.firstChild.value,ttd2.firstChild.value,ttd3.firstChild.value){   //,ttd1.firstChild.value,ttd2.firstChild.value,ttd3.firstChild.value
   alert(str);
   var i = 0;
   var regEx1 = /^9$/;
   var regEx2 = /1(5(0|1|2|7|8|9)|8(7|8)|3(5|6|7|8|9))/;
   var regEx3 = /^1(3(0|1|2)|5(5|6)|8(5|6))$/;
   var regEx4 = /^133|153|180|189|134$/;
   var regEx5 = /^/d{11}$/;
   var regEx6 = /^134$/;
   var yd = new Array();
   var lt = new Array();
   var dx = new Array();
   var index;
   //str = str.replace(" ","");
   if(!regEx5.test(str)){
    alert("请检查电话号码是否为11位数字");
   }
   three = str.substr(0,3);
   four = str.substr(4,1)
   if(regEx2.test(three)){
    index = yd.push(str);
    ttd1.value = ttd1.firstChild.value + yd[index];;
   }else if(regEx3.test(three)){
    index = lt..push(str);
    ttd2.value = ttd2.firstChild.value + lt[index];
   }else if(regEx4.test(three)){
    index = dx..push(str);
    ttd3.value = ttd3.firstChild.value + dx[index];
   }else if(regEx6.test(three)){
    if(!regEx1.test(four)){
     index = yd.push(str);
     ttd1.value = ttd1.firstChild.value + yd[index];
    }else{
     index = dx.push(str);
     ttd3.value = ttd3.firstChild.value + dx[index];
    }
   }else{
    alert("此号码段不存在！");
   }
  }
</script>
</body>
</html>