鱼之天空的博客

Beat the Spread!Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 7144    Accepted Submission(s): 3783Problem DescriptionSuperbowl

Balloon Comes!Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 30678    Accepted Submission(s): 11574Problem DescriptionThe conte

PerfectionTime Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 3006    Accepted Submission(s): 1838Problem DescriptionFrom the articl

The SnailTime Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 2954    Accepted Submission(s): 2129Problem DescriptionA snail is at th

最简单的计算机Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 7946    Accepted Submission(s): 4471Problem Description一个名叫是PigHeadThree的

问题解析：　　数学归纳法

回文数猜想Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 7399    Accepted Submission(s): 4533Problem Description一个正整数，如果从左向右读（称之为正序数

随手改了改1004，就通过了，就是占的空间比较大。#include#includeusing namespace std;int main(){    map aa;    int s;    int num;    while(cin>>num&&num>0)    {        aa.clear();        while(num--) 

整理出来表达式就很好写了，果然是水题一枚#include using namespace std;int main(){ double n; double sum; int i; int num; while(cin >> n,n) { sum=0; num=0; for(i = 2; sum<n

盐水的故事Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 20056    Accepted Submission(s): 5097Problem Description挂盐水的时候，如果滴起来有规律，先是滴

不熟悉map的筒子们可以研究一下#include#include#includeusing namespace std;int main(){ map aa; string s; int num; while(cin>>num&&num>0) { aa.clear(); while(num--) {

这道题注意一下格式就行了#include using namespace std;int main(){ int a; while(cin >> a) { int sum = 0; for(int i = 1; i <=a;i++) sum+=i; cout << sum << endl;

值得注意的是，并不是从第一个开始计算，需要自己查找#include using namespace std; int main() { int t,n,temp,pos1,pos2,max,now,x,i,j; cin>>t; for (i=1;i<=t;i++) { cin>>n>>temp;

AC MeTime Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 19031    Accepted Submission(s): 8031Problem DescriptionIgnatius is doing

Who's in the MiddleTime Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 19136    Accepted Submission(s): 8425Problem DescriptionFJ is

18岁生日Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 33330    Accepted Submission(s): 10810Problem DescriptionGardon的18岁生日就要到了，他

说明：虽然看英语没怎么懂，但看了例子大致知道意思了，就是一个数各个位上的和，在十进制，十二进制，十六进制的时候相等

A+B ComingTime Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 9659    Accepted Submission(s): 6309Problem DescriptionMany classmates