题目来源:牛客网
有这样一道智力题:“某商店规定:三个空汽水瓶可以换一瓶汽水。小张手上有十个空汽水瓶,她最多可以换多少瓶汽水喝?”答案是5瓶,方法如下:先用9个空瓶子换3瓶汽水,喝掉3瓶满的,喝完以后4个空瓶子,用3个再换一瓶,喝掉这瓶满的,这时候剩2个空瓶子。然后你让老板先借给你一瓶汽水,喝掉这瓶满的,喝完以后用3个空瓶子换一瓶满的还给老板。如果小张手上有n个空汽水瓶,最多可以换多少瓶汽水喝?
解题思路:
因为两个空瓶可以完全兑换一瓶汽水,那么我可以每次拿出两个空瓶换一瓶汽水,也没有空瓶留下,这种兑换的次数一共有n / 2次,所以一共可以得到n / 2瓶汽水。
代码实现:
public class DrinkJuiceEmptyBottle {
private static final int ZERO = 0;
private static final int TWO = 2;
private static final int THREE = 3;
public static void main(String[] args) {
drink(67);
}
public static void drink(int num) {
Scanner sc = new Scanner(System.in);
while (sc.hasNext()) {
int total = ZERO;
while (num > TWO) {
total += num / THREE;
num = num / THREE + num % THREE;
}
if (num == TWO) {
total++;
}
System.out.println(total);
}
}
}