python 矩阵转置

最新推荐文章于 2025-10-11 00:39:30 发布

原创最新推荐文章于 2025-10-11 00:39:30 发布 · 6.7k 阅读

14 ·

CC 4.0 BY-SA版权

文章标签：

#矩阵 #python #线性代数

python 专栏收录该内容

15 篇文章

订阅专栏

本文介绍了如何使用Python对矩阵进行转置操作，包括两种不同的实现方式：列表推导式和循环迭代。通过实例展示了3X4矩阵转为4X3矩阵的过程，详细解释了代码的工作原理。

python 矩阵转置

matrix = [
...     [1, 2, 3, 4],
...     [5, 6, 7, 8],
...     [9, 10, 11, 12],
... ]

以下实例将3X4的矩阵列表转换为4X3列表：

[[row[i] for row in matrix] for i in range(4)]
[[1, 5, 9], [2, 6, 10], [3, 7, 11], [4, 8, 12]]

>>> transposed = []
>>> for i in range(4):
...     transposed.append([row[i] for row in matrix])
...
>>> transposed
[[1, 5, 9], [2, 6, 10], [3, 7, 11], [4, 8, 12]]

>>> transposed = []
>>> for i in range(4):
...     # the following 3 lines implement the nested listcomp
...     transposed_row = []
...     for row in matrix:
...         transposed_row.append(row[i])
...     transposed.append(transposed_row)
...
>>> transposed
[[1, 5, 9], [2, 6, 10], [3, 7, 11], [4, 8, 12]]