name that number

最新推荐文章于 2023-12-26 10:22:35 发布

Raypenper

最新推荐文章于 2023-12-26 10:22:35 发布

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CC 4.0 BY-SA版权

本文链接：https://blog.youkuaiyun.com/meillo2017/article/details/87976894

本文介绍了一个使用C语言编写的程序，该程序能够将电话按键输入的数字序列转换为可能对应的名字。通过读取一个字典文件，程序将每个字母映射到相应的数字，并比较输入的数字序列与字典中的名字，找到匹配项并输出。

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#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main() 
{
    FILE *in = fopen ("namenum.in", "r");
    FILE *in2 = fopen ("dict.txt", "r");
    FILE *out = fopen ("namenum.out","w");
    int nsolutions = 0;
    int numlen;
    char word[80], num[80], *p, *q, map[256];
    int i, j;
    map['A'] = map['B'] = map['C'] = '2';
    map['D'] = map['E'] = map['F'] = '3';
    map['G'] = map['H'] = map['I'] = '4';
    map['J'] = map['K'] = map['L'] = '5';
    map['M'] = map['N'] = map['O'] = '6';
    map['P'] = map['R'] = map['S'] = '7';
    map['T'] = map['U'] = map['V'] = '8';
    map['W'] = map['X'] = map['Y'] = '9';
    fscanf (in, "%s",num);
    numlen = strlen(num);
    while (fscanf (in2, "%s", word) != EOF) 
    {
        for (p=word, q=num; *p && *q; p++, q++) 
        {
            if (map[*p] != *q)
                break;
        }
        if (*p == '\0' && *q == '\0') 
        {
            fprintf (out, "%s\n", word);
            nsolutions++;
        }
    }
    if (nsolutions == 0) fprintf(out,"NONE\n");
    return 0;
}