poj2272

题目大意：

给两个人每个人3组坐标，共计12个数，按照图片的分数相加，问谁赢

解题思路：

简单计算比较即可

代码如下：

#include<iostream>
#include<cmath>
using namespace std;

int main()
{
  int sum1,sum2;
  double a1,b1,a2,b2,a3,b3;
  double x1,y1,x2,y2,x3,y3;
  while(scanf("%lf%lf%lf%lf%lf%lf%lf%lf%lf%lf%lf%lf"
  ,&a1,&b1,&a2,&b2,&a3,&b3,&x1,&y1,&x2,&y2,&x3,&y3)!=EOF)
  {
    sum1=sum2=0;
    if(abs(a1+100)<1e-6)
    {
      break;
    }
    double r=sqrt(a1*a1+b1*b1);
    if(r<=3) sum1+=100;
    else if(r<=6)   sum1+=80;
    else if(r<=9)   sum1+=60;
    else if(r<=12)  sum1+=40;
    else if(r<=15)  sum1+=20;
    r=sqrt(a2*a2+b2*b2);
    if(r<=3) sum1+=100;
    else if(r<=6)   sum1+=80;
    else if(r<=9)   sum1+=60;
    else if(r<=12)  sum1+=40;
    else if(r<=15)  sum1+=20; 
    r=sqrt(a3*a3+b3*b3);
    if(r<=3) sum1+=100;
    else if(r<=6)   sum1+=80;
    else if(r<=9)   sum1+=60;
    else if(r<=12)  sum1+=40;
    else if(r<=15)  sum1+=20;
    r=sqrt(x1*x1+y1*y1);
    if(r<=3) sum2+=100;
    else if(r<=6)   sum2+=80;
    else if(r<=9)   sum2+=60;
    else if(r<=12)  sum2+=40;
    else if(r<=15)  sum2+=20;
    r=sqrt(x2*x2+y2*y2);
    if(r<=3) sum2+=100;
    else if(r<=6)   sum2+=80;
    else if(r<=9)   sum2+=60;
    else if(r<=12)  sum2+=40;
    else if(r<=15)  sum2+=20;
    r=sqrt(x3*x3+y3*y3);
    if(r<=3) sum2+=100;
    else if(r<=6)   sum2+=80;
    else if(r<=9)   sum2+=60;
    else if(r<=12)  sum2+=40;
    else if(r<=15)  sum2+=20;
    if(sum1>sum2)
    {
      printf("SCORE: %d to %d, PLAYER 1 WINS.\n",sum1,sum2);
    }
    else if(sum1<sum2)
    {
      printf("SCORE: %d to %d, PLAYER 2 WINS.\n",sum1,sum2);
    }
    else
    {
      printf("SCORE: %d to %d, TIE.\n",sum1,sum2);
    }
  }
  return 0;
}