LeetCode 209. Minimum Size Subarray Sum

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本文介绍了解决LeetCode 209题目的方法，该题目要求找到一个连续子数组，使得其元素之和大于等于给定的目标值，并返回满足条件的最小子数组长度。通过滑动窗口算法实现，有效地解决了这一问题。

LeetCode 209. Minimum Size Subarray Sum

Description

Given an array of n positive integers and a positive integer s, find the minimal length of a contiguous subarray of which the sum ≥ s. If there isn’t one, return 0 instead.

For example, given the array [2,3,1,2,4,3] and s = 7,
the subarray [4,3] has the minimal length under the problem constraint.

    class Solution {
        public int minSubArrayLen(int s, int[] nums) {
            int i = 0, j = -1;
            int ans = nums.length + 1;
            int sum = 0;
            while (i < nums.length) {
                if(sum < s && j + 1 < nums.length) {
                    sum += nums[++j];
                }
                else {
                    sum -= nums[i++];
                }
                if(sum >= s) {
                    ans = Math.min(ans, j - i + 1);
                }
            }
            if (ans == nums.length + 1)
                return 0;
            return ans;
        }
    }