(java)leetcode Delete Node in a Linked List

Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.

Supposed the linked list is 1 -> 2 -> 3 -> 4 and you are given the third node with value 3, the linked list should become 1 -> 2 -> 4 after calling your function.

思路：当前节点的值等于下一个节点，当前节点的下一个节点等于下一个节点的下一个节点

代码如下(已通过leetcode)

/**
 * Definition for singly-linked list.
 * public class ListNode {
 *     int val;
 *     ListNode next;
 *     ListNode(int x) { val = x; }
 * }
 */
public class Solution {
    public void deleteNode(ListNode node) {
        if(node==null) return;
        node.val=node.next.val;
        node.next=node.next.next;
    }
}