Given an array where elements are sorted in ascending order, convert it to a height balanced BST.
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/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
TreeNode* foo(vector<int>& nums, int left, int right)
{
if (left > right)
return NULL;
int mid = (left+right)/2;
TreeNode *node = new TreeNode(nums[mid]);
node->left = foo(nums, left, mid-1);
node->right = foo(nums, mid+1, right);
return node;
}
public:
TreeNode* sortedArrayToBST(vector<int>& nums) {
return foo(nums, 0, nums.size()-1);
}
};