大小字母反转算法

题目：将大小字母反转

思路：大小字母对应的编码的值为32

package huaweiicomeagain;
/**
 * 大小字母反正
 * @author huanghuankun
 *
 */
public class CharReverse {
	public static void main(String[] args){
		String srcStr = "SFDFWEFdefewfwDFEWF";
		String regex = "^[A-Z a-z]*$";
		boolean flag = srcStr.matches(regex);
		System.out.println("srcStr="+srcStr);
		if(flag){
			String dstStr = charReverse(srcStr);
			System.out.println("dstSrc="+dstStr);
		}else{
			System.out.println("Wrong input.");
		}
	}

	private static String charReverse(String srcStr) {
		// TODO Auto-generated method stub
		String dstStr = "";
		char ch;
		for(int i=0;i<srcStr.length();i++){
			if('A'<srcStr.charAt(i) && srcStr.charAt(i)<'Z'){
				ch = (char) (srcStr.charAt(i)+32);
				dstStr += String.valueOf(ch);
			}else{
				ch = (char) (srcStr.charAt(i)-32);
				dstStr += String.valueOf(ch);
			}
		}
		return dstStr;
	}
}

结果：

srcStr=SFDFWEFdefewfwDFEWF
dstSrc=sfdfwefDEFEWFWdfewf