Comparing Object Values Using Hash Codes

博客介绍了哈希码通常用于高效比较两个对象的值,若两对象哈希码不同则值不同,相同则需进一步确认。好的哈希码算法能减少不同值有相同哈希码的概率。还提到`'`运算符可判断两对象是否相同,特定应用中可能需获取对象的标识哈希码,如哈希表。
Comparing Object Values Using Hash CodesThe hash code of an object is an integer value that's computed using the value of the object. For example, for a String object, the characters of the string are used to compute the hash code. For an Integer object, the integer value is used to compute the hash code.

Hash codes are typically used as an efficient way of comparing the values of two objects. For example, if the hash code of the string "hello" is 33, another String object with the same contents would also a hash code of 33.

If the hash codes of two object values are different, the object values are guaranteed to be different. However, if the hash codes of two object values are the same, the object values are not guaranteed to be the same. An additional call to Object.equals() must be made to confirm that the object values are the same. A good hash code algorithm will minimize the chance of two different values having the same hash code.

The `==' operator is the most efficient way to determine if two objects (rather than object values) are the same. However, in very limited applications, it may be necessary to get the hash code of an object (called the identity hash code) rather than of the object value. For example, a hash table of objects requires the use of the identity hash code.

 File file1 = new File("a"); File file2 = new File("a"); File file3 = new File("b"); // Get the hash codes int hc1 = file1.hashCode(); // 1234416 int hc2 = file2.hashCode(); // 1234416 int hc3 = file3.hashCode(); // 1234419 // Check if two object values are the same if (hc1 == hc2 && file1.equals(file2)) { // They are the same } // Get the identity hash codes int ihc1 = System.identityHashCode(file1); // 1027049 int ihc2 = System.identityHashCode(file2); // 14642381 int ihc3 = System.identityHashCode(file3); // 6298545 
### Java 中使用 `Comparator.comparing` 对 `List<Map<String, Object>>` 排序 为了实现对 `List<Map<String, Object>>` 的排序操作,可以利用 `Comparator.comparing()` 方法来创建比较器。此方法允许指定用于提取键值的函数,并基于该键对应的值来进行排序。 下面是一个具体的例子,展示如何按照特定字段(假设为 "age" 字段)对列表中的映射对象进行升序排列: ```java import java.util.*; import java.util.stream.Collectors; public class SortExample { public static void main(String[] args) { // 创建一个包含多个 Map 的 List 集合 List<Map<String, Object>> list = Arrays.asList( new HashMap<>() {{ put("name", "Alice"); put("age", 30); }}, new HashMap<>() {{ put("name", "Bob"); put("age", 25); }}, new HashMap<>() {{ put("name", "Charlie"); put("age", 35); }} ); // 使用 Comparator.comparing() 和 map.get() 来获取要排序的关键字并执行排序 List<Map<String, Object>> sortedList = list.stream() .sorted(Comparator.comparing(o -> (Comparable) o.get("age"))) .collect(Collectors.toList()); System.out.println(sortedList); } } ``` 这段代码首先定义了一个由哈希表组成的列表,其中每个哈希表代表一个人的信息记录。接着通过流式 API 调用 `sorted()` 函数,并传入自定义的比较器逻辑——即根据 `"age"` 键所关联的对象大小决定顺序[^1]。 需要注意的是,在实际应用中应当确保所有目标键存在以及其对应的数据类型一致以便于正确比较;如果不确定,则可能需要额外处理异常情况或提供默认值。
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