acm hnu 10189 Speed Limit (easy)

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本文介绍了一种计算基于时间记录和速度的总行驶距离的方法，并提供了一个简单的C语言程序示例。

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Speed Limit

Time Limit: 1000ms, Special Time Limit:2500ms, Memory Limit:32768KB

Total submit users: 164, Accepted users: 162

Problem 10189 : No special judgement

Problem description

Bill and Ted are taking a road trip. But the odometer in their car is broken, so they don't know how many miles they have driven. Fortunately, Bill has a working stopwatch, so they can record their speed and the total time they have driven. Unfortunately, their record keeping strategy is a little odd, so they need help computing the total distance driven. You are to write a program to do this computation. For example, if their log shows Speed in miles perhour Total elapsed time in hours 20 2 30 6 10 7 this means they drove 2 hours at 20 miles per hour, then 6-2=4 hours at 30 miles per hour, then 7-6=1 hour at 10 miles per hour. The distance driven is then (2)(20) + (4)(30) + (1)(10) = 40 + 120 + 10 = 170 miles. Note that the total elapsed time is always since the beginning of the trip, not since the previous entry in their log.

Input

The input consists of one or more data sets. Each set starts with a line containing an integer n, 1 <= n <= 10, followed by n pairs of values, one pair per line. The first value in a pair, s, is the speed in miles per hour and the second value, t, is the total elapsed time. Both s and t are integers, 1 <= s <= 90 and 1 <= t <= 12. The values for t are always in strictly increasing order. A value of -1 for n signals the end of the input.

Output

For each input set, print the distance driven, followed by a space, followed by the word "miles"

Sample Input

Sample Output

170 miles
180 miles
90 miles

Problem Source

Mid-Central USA 2004

/*10:40*/
#include <stdio.h>

main()
{
  int i,j,k,n;
  int v=0,t=0,vinput,telapse,miles;
  scanf("%d",&n);
  while(n!=-1){
    v=0;
    t=0; //pre speed time
    miles=0;
    for(i=0;i<n;i++){
        scanf("%d%d",&vinput,&telapse);
        miles+=(telapse-t)*vinput;
        t=telapse;
    }
    printf("%d miles ",miles);

    scanf("%d",&n);
  }
  return 0;
}