两个线程交叉打印（最简单的）

最新推荐文章于 2022-12-16 19:26:22 发布

原创最新推荐文章于 2022-12-16 19:26:22 发布 · 1.5k 阅读

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#两个线程交互

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本文探讨了并发环境下线程间的同步问题，通过实现线程A和线程B，展示了如何利用业务逻辑来控制线程执行顺序。通过实例演示了使用`synchronized`关键字和条件等待机制来确保线程安全和有序执行。

A:线程：

package Thread.a.b.turn;

public class ThreadA implements Runnable {
private ThreadBusiness treadMian =null;
public ThreadA(ThreadBusiness threadMain ){
this.treadMian=threadMain;
}

public void run() {
// TODO Auto-generated method stub

for(int i=0;i<10;i++){
treadMian.printA();
}
}

}

B线程：

package Thread.a.b.turn;

public class ThreadB implements Runnable {
private ThreadBusiness treadMian =null;
public ThreadB(ThreadBusiness threadMain ){
this.treadMian=threadMain;
}
public void run() {
// TODO Auto-generated method stub
for(int i=0;i<10;i++){
treadMian.printB();
}
}

}

业务逻辑：

package Thread.a.b.turn;

public class ThreadBusiness {
public boolean flag=true;

public synchronized void printA(){
if(!flag){
try {
wait();
} catch (InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
flag=false;
System.out.println("A");
notify();
}

public synchronized void printB(){
if(flag){
try {
wait();
} catch (InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
flag=true;
System.out.println("B");
notify();
}

}

测试：

package Thread.a.b.turn;

public class TestThreadAB {
public static void main(String args[]){
//先让A线程打印，后让B线程打印
ThreadBusiness threadMain = new ThreadBusiness();
Thread a = new Thread(new ThreadA(threadMain),"A");
Thread b = new Thread(new ThreadB(threadMain),"B");
a.start();
b.start();
}
}

希望大家赐教。