C语言_求1-1/2+1/3-......+1/99-1/100的值

#include "stdio.h"
int main(){
    int num=1;
    double count,sum=1,deno=2;
    while (deno<=100) {
        num=-num;
        count=num/deno;
        deno=deno+1;
        sum=sum+count;
    }
    printf("总数是:%f",sum);
    return 0;
}