java之Map对象转java对象的两种简单方式

我们在处理数据的时候，经常用到map对象转java对象，下面我们用代码演示下，希望能够帮助到有这方面需求的老哥。

要转换的java对象：

public class Person {

    private Integer id;

    private String name;

    private Integer age;

    private String job;

    public Person() {}


    public Person(Integer id, String name, Integer age, String job) {
        this.id = id;
        this.name = name;
        this.age = age;
        this.job = job;
    }

    public Integer getId() {
        return id;
    }

    public void setId(Integer id) {
        this.id = id;
    }

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public Integer getAge() {
        return age;
    }

    public void setAge(Integer age) {
        this.age = age;
    }

    public String getJob() {
        return job;
    }

    public void setJob(String job) {
        this.job = job;
    }


    @Override
    public String toString() {
        return "Person{" +
                "id=" + id +
                ", name='" + name + ''' +
                ", age=" + age +
                ", job='" + job + ''' +
                '}';
    }
}

定义个map集合

Map<String,Object>  map = new HashMap<>();
        map.put("id",1);
        map.put("name","宋圆圆");
        map.put("age",25);
        map.put("job","技术总监");

打印如下：

第一种方式使用JSONArray

     JSONObject jsonObject = new JSONObject();
          jsonObject.putAll(map);
          Person person = jsonObject.toJavaObject(Person.class);

打印输出person

第二种方式实现：自定义工具类

public class MapBeanUtils {


    public static <T> T mapToBean(Map<String, Object> map, Class<T> class1) {

   T bean = null;

   try {

  bean = class1.newInstance();

  BeanUtils.populate(bean, map);

  } catch (InstantiationException e) {

  e.printStackTrace();

   } catch (IllegalAccessException e) {

e.printStackTrace();

 } catch (InvocationTargetException e) {

  e.printStackTrace();
   }

   return bean;

   }

}

  Person person = MapBeanUtils.mapToBean(map, Person.class);

打印：

注意事项：map的key一定要和bean的属性保持一致。