m0_65594779的博客

33、杨辉三角

#include<stdio.h>#include <math.h>int main(){ for(int x=1; ; x++) { int n=x*x; if(n<1000)continue; if(n>9999)break; int hi=n/100; int lo=n%100; if(hi/10==hi%10&&lo/10==lo%10)

#include<stdio.h>int main(){ int n; scanf("%d",&n); for(int i=1; i<=n; i++) { printf("%d ",i); } return 0;}

输入三个整数，从小到大排序后输出。样例输入20 7 33样例输出7 20 33#include <stdio.h>int main(){ int a, b,c,t; scanf("%d%d%d", &a, &b,&c); if(a>b) { t=a; a=b; b=t; } if(a>c) { t=a;

已知鸡和兔的总数量为n，总腿数为m。输入n和m，依次输出鸡的数目和兔的数目。如果无解，则输出No answers。分析：设鸡有a只，兔有b只，则a+b=n，2a+4b=m，联立可求出a，b。#include<stdio.h>int main(){ int a,b,n,m; scanf("%d%d",&n,&m); a=(4*n-m)/2; b=n-a; if(m/2==1||a<0||b<0) {

1.三变量法：#include<stdio.h>int main(){ int a,b,t; scanf("%d%d",&a,&b); t=a; a=b; b=t; printf("%d %d\n",a,b); return 0;}2.#include<stdio.h>int main(){ int a,b; scanf("%d%d",&a,&b

#include<stdio.h>int main(){ int n,a,b,c; scanf("%d",&n); a=n/100; b=n/10%10; c=n%10; printf("%d%d%d",c,b,a); return 0;}#include<stdio.h>int main(){ int n,m; scanf("%d",&n);

#include<stdio.h>#include <math.h>int main(){ double r; double h; double area; const double pi=acos(-1.0);//常量pi scanf("%lf%lf",&r,&h);//注意%lf area=pi*r*r*2+2*pi*r*h; printf("%.3f\n",area); return 0;}