Java每日一练03多线程模拟赛跑实现方式，一手顺牌

muskfans

于 2021-12-30 16:01:40 发布

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文章标签： java 开发语言后端

本文链接：https://blog.youkuaiyun.com/m0_54608045/article/details/122230495

本文介绍了使用Java的倒计时门闩（CountDownLatch）来模拟赛跑场景，同时讲解了如何检测手牌数组是否能组成顺子的逻辑。

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Java每日一练03

倒计时门闩模拟赛跑
检测手牌数组是否可以构成顺子

倒计时门闩模拟赛跑

import java.util.concurrent.CountDownLatch;
import java.util.concurrent.ExecutorService;
import java.util.concurrent.Executors;

public class CountDownLatchTest {
   
   
    private static final int RUNNER_COUNT = 10;
    public static void main(String[] args) throws InterruptedException {
   
   
        final CountDownLatch begin = new CountDownLatch(1);
        final CountDownLatch end = new CountDownLatch(RUNNER_COUNT);
        final ExecutorService exec = Executors.newFixedThreadPool(RUNNER_COUNT);

        for (int i = 0; i < RUNNER_COUNT; i++) {
   
   
            // 选手编号
            final int NO = i + 1;
            Runnable run = new Runnable() {
   
   
                @Override
                public void run() {
   
   
                    try {
   
   
                        begin.await();
                        // 模拟两名选手到达终点的时间差，时间差不超过10秒</