
pat乙级
cyqx123
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待处理pat B1054
待处理patB1054题目链接如下:添加链接描述代码如下:#include<iostream>#include<string>#include<algorithm>#include<deque>using namespace std;bool xiaoshu(string s) { string s3; for (int i = 0; i < s.size(); i++) { if (s[i] == '.') { st原创 2021-04-24 19:47:55 · 143 阅读 · 0 评论 -
pat B1081
pat B1081题目链接如下:添加链接描述注意:用户的输入可能有空格,使用getline()获得密码的输入。所给用例没有这种情况:只有小数点,且长度不小于6.代码如下:#include<iostream> #include<deque>#include<string>#include<algorithm>using namespace std;int main() { int N; deque<string> id原创 2021-04-24 16:29:24 · 151 阅读 · 0 评论 -
待处理 pat B1025
##待处理 pat B1025题目链接如下:添加链接描述代码如下:#include <iostream>#include<string>#include<unordered_map>#include<deque>struct Node { int data; int add; int next;}node[110000],d;using namespace std;int main() { int begin, N, K;原创 2021-04-21 16:33:52 · 110 阅读 · 0 评论 -
pat B1016
pat B1016添加链接描述代码如下:#include<iostream>#include<string>#include<deque>using namespace std;int main() { string a, b,da, db; cin >> a >> da >> b >> db; int hash1[128] = { 0 }; int hash2[128] = { 0 }; for原创 2021-04-19 23:27:52 · 68 阅读 · 0 评论 -
pat B1019
pat B1019题目链接如下:添加链接描述代码如下:#include <iostream>#include<string>#include<algorithm>using namespace std;bool higher(int a, int b) { return a > b;}int main() { string s1(4, 0); cin >> s1; for (int i = 0; i < s1.s原创 2021-04-19 21:09:34 · 64 阅读 · 0 评论 -
pat B1039
pat B1039题目链接如下:添加链接描述代码如下:#include<deque>#include<iostream>#include<string>using namespace std;int main() { string s1, s2; cin >> s1 >> s2; deque<int> hash(128, 0); for (int i = 0; i < s2.size(); i++) {原创 2021-04-19 19:33:43 · 86 阅读 · 0 评论 -
pat B1041
pat B1041题目链接如下:添加链接描述代码如下:#include <iostream>#include<string>#include<deque>struct Person { std::string str1; int num1; int num2;}p[1100], d;using namespace std;int main() { int N; cin >> N; for (int i = 0; i <原创 2021-04-18 08:27:18 · 112 阅读 · 0 评论 -
pat B1009
pat B1009题目链接如下:添加链接描述代码如下:方法一:#include<deque>#include<iostream>#include<string>using namespace std;int main() { string s; deque<string> ideq; while (cin >> s) { ideq.push_back(s); } for (int i = ideq.size() -原创 2021-04-18 01:56:37 · 102 阅读 · 0 评论 -
pat B1006
pat B1013题目链接如下:添加链接描述代码如下:#include <iostream>#include <string> using namespace std;int main() { string s1; cin >> s1; if (s1.size() == 3) { for (int i = 0; i < s1[0] - '0'; i++) cout << "B"; } if (s1.size() >= 2)原创 2021-04-17 21:21:30 · 71 阅读 · 0 评论 -
pat B1004
pat B1004题目链接如下https://pintia.cn/problem-sets/994805260223102976/problems/994805321640296448代码如下#include<iostream>#include<string>#include<algorithm>using namespace std;struct Student { string name1,name2; int grades;}stu[100原创 2021-04-17 18:30:45 · 102 阅读 · 0 评论 -
pat B1093
待处理pat B1093题目如下添加链接描述代码如下#include <iostream>#include<string>using namespace std;int main() { ios::sync_with_stdio(false); cin.tie(0); string s,s1,s2; getline(cin, s); getline(cin, s1); s2 = s + s1; auto it = s2.begin(); for原创 2021-04-13 20:43:40 · 95 阅读 · 0 评论 -
pat B1043
pat B1043题目链接如下:添加链接描述代码如下:#include <iostream>#include <string>#include<deque>#include <algorithm>using namespace std;int main() { deque<int> hash(128,0); string s, out = "PATest"; cin >> s; int sum = 0;//统原创 2021-04-17 17:23:57 · 65 阅读 · 0 评论 -
pat B1028
pat B1028题目链接如下添加链接描述代码如下:#include <iostream>#include <string> #include <deque>#include <algorithm>using namespace std;struct Person { //定义结构体 string name; int year; int month; int day;}p[100010],d;bool原创 2021-04-17 01:13:58 · 88 阅读 · 0 评论 -
pat B1031
pat B1031题目链接如下添加链接描述代码如下:#include<iostream>#include<string>#include<deque> #include <algorithm>using namespace std;int main() { int N; cin >> N; string s, s1; deque<bool> pass(N, true); int weight[17] = {原创 2021-04-16 00:46:18 · 76 阅读 · 0 评论 -
pat B1042
pat B1042题目链接如下添加链接描述代码如下#include<iostream>#include<deque>#include<string>#include <algorithm>using namespace std;int main() { deque<int> hash(128, 0); string s1; getline(cin, s1); for (int i = 0; i < s1.siz原创 2021-04-14 23:41:08 · 86 阅读 · 0 评论 -
pat B1033
pat B1033题目链接如下添加链接描述代码如下#include <iostream>#include <string>#include <stdlib.h>#include <deque>using namespace std;bool hashTable[256];int main() { deque <bool> hash(128, 0); string s1, s2; getline(cin, s1); ge原创 2021-04-14 21:18:26 · 98 阅读 · 0 评论 -
pat B1076
pat B1076解法一:#include<iostream>#include<string> using namespace std;using gg = long long;int main() { ios::sync_with_stdio(false); gg N, n; cin >> N; n = N * 4; string s1, s; for (int i = 0; i < n; i++) { cin >>原创 2021-04-13 15:39:26 · 65 阅读 · 0 评论