m0_49040755的博客

【代码】TransCrowd: weakly-supervised crowd counting with transformers；使用transformer进行弱监督的人群计数。

很遗憾的是作者没能实现论文中的损失函数。论文中各模块的通道数与官方版本略有出入。

本文中对CSRNet: Dilated Convolutional Neural Networks for Understanding the Highly Congested Scenes（CVPR 2018）中的模型进行pytorch实现。

【代码】Initializing libiomp5md.dll, but found libiomp5md.dll already initialized解决方案。

本文所实现的网络来源于SCAR:Spatial-/Channel-wise Attention Regression Networks for Crowd Counting（Neurocompting 2019）

MCNN实现

注意事项见注释import matplotlib.pyplot as pltimport matplotlib.patches as pplt.rcParams["font.sans-serif"]=["SimHei"]plt.rcParams["axes.unicode_minus"]=0['坐标轴',["轴脊"],['刻度',['刻度线'],['刻度标签']]]'向任意位置添加坐标轴'ax=plt.axes((0.31,0.42,0.3,0.4))#该坐标轴距离左侧0.31，距离底部0.4

代码如下，解析见注释from numpy.core.fromnumeric import shapefrom sklearn.neural_network import MLPClassifierfrom sklearn.datasets import load_digitsimport osfrom sklearn.model_selection import train_test_splitimport numpy as npiris = load_digits()x = iris['

matplotlib常见图表美化函数import matplotlib.pyplot as pltimport matplotlib.style as msms.use("fivethirtyeight")#切换风格plt.rcParams["font.sans-serif"]=["SimSun"]#宋体x=list(range(1,13))y1=[39,20,40,38,42,43,41,41,45,48,52,50]y2=[45,28,48,49,50,51,50,50,51,52,70

直接上代码（此处生成2个，每个文件生成20个随机单词，以空格分割）from random_words import RandomWords as rfor i in range(2): a = open("d:\\hi{}.txt".format(i), 'w') w=[] for i in range(20): word = r().random_word() w.append(word) z = ' '.join(w) a.wr

常用的matplotlib绘图所用的辅助函数

去掉注释即可使用import matplotlib.pyplot as pltimport numpy as npplt.rcParams["font.sans-serif"]=["SimHei"]#设置字体plt.rcParams["axes.unicode_minus"]=0#让负数也能正常表示x=[1,2,3,4,5,6]y=[10,9,3,2,5,6]# plt.plot(x,y,"m-8",label="看")#分别指定线的形状，颜色，标记# plt.show()y1=[8,12

在有序数组中查找指定数字可以使用二分查找，二分查找有极低的时间复杂度，代码实现如下int bin_searh(int arr[],int k,int sz){// k为要查找的元素，sz是数组的长度 int l=0; int r=sz-1; while(l<=r){ int mid=(l+r)/2; printf("%d\n",mid); if (arr[mid]<k) { l=mid+1;

思路为将nums1中的0换为nums2的数随后对nums2进行排序class Solution: def merge(self, nums1: List[int], m: int, nums2: List[int], n: int) -> None: """ Do not return anything, modify nums1 in-place instead. """ b=0 for i in ran.

直接上代码ArrayList 实现public class nov_23 { public static void main(String[] args) { ArrayList list = new ArrayList(); for (int i=0 ;i<20;i++){ list.add(i+1); } Random r = new Random(); System.out.println

题目描述如下代码如下# Definition for singly-linked list.# class ListNode:# def __init__(self, val=0, next=None):# self.val = val# self.next = nextclass Solution: def addTwoNumbers(self, l1: ListNode, l2: ListNode) -> ListNode:

直接上代码import matplotlib.pyplot as pltplt.rcParams['font.sans-serif']=['SimHei']plt.rcParams["axes.unicode_minus"]=0import numpy as npmonth=np.arange(1,13,1)d_p=[2.6,5.9,9,34,28,70,123,154,23,12,3,2]d_e=[2.3,4.6,7,23.2,25.6,76.7,135.6,162.2,32.3,20,6.

人狠话不多，直接上代码abstract class solver{//模糊类 public abstract void getArea(); // 获取面积 public abstract void getPan(); // 获取周长}class rectangle extends solver{//长方形 private double a; private double b; public void getPan() { double c=