CCF 201909-1 小明种苹果(Python满分)
问题描述
代码实现
n,m = map(int,input().split())
alist = []
final_count = 0
suguo_count = [[i+1,0] for i in range(n)] #创建疏果二维数组
def abs_sum(li):
ab = 0
for i in range(1,len(li)):
ab += abs(li[i])
return ab
for j in range(n):
d = list(map(int,input().split()))
suguo_count[j][1] = abs_sum(d)
final_count += d[0]-suguo_count[j][1]
l = sorted(suguo_count,key = lambda x: (x[1],-x[0]))
print(final_count,l[n-1][0],l[n-1][1],end=' ')